Matt McCullar was kind enough to remind me of a little formula for
calculating a required load.
volts/amps = resistance (ohms)
volts*amps = power (watts)
So, assuming we have an Atari board that needs 5 volts and draws 3 amps,
that gives us an equivalent load of 2 ohms at 15 watts.
I guess if you wanted to check the 22V output of the ARII (staying
strictly vector), you could use a 7 ohm, 65 watt resistor as well.
I hope I got my math right... :)
tom
John Robertson wrote:
>
> That is a very light load - only about 200ma @ 5VDC, I use a 1 ohm 25
> to 50 watt resistor as a load for testing powers supplies. That is 1
> amp @ 5VDC, and is a reasonable load for any power supply. I think it
> would be good to just short the sense resistors out, as they only seem
> good to burn up, and you can adjust the supply manually for the
> correct voltage.
>
> John :-#)#
>
> At 02:22 AM 28/05/2001, you wrote:
>
> > What's a good sized load to use when testing these? I have been
> > using a 22ohm 5W from +5 to Gnd. +Sense tied to +5 -Sense tied to
> > Gnd.
> >
> > Reasonable?
> >
> >
> > Also what do you think of the idea of tying the sense's to there
> > respective values at the AR2. Keep them from burning up the sense
> > resistors quite so easily, though I realize it will pretty much
> > disable the wire harness loss sensing.
> >
> >
> > Open to tomato's.
> >
> >
> > David
> >
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