>X(t) = X0 + (dX)t + (ddx)(t)(t-1)/2
>Y(t) = Y0 + (dY)t + (ddy)(t)(t-1)/2
Wait, wait... I'm getting a vision-- something coming back to me from
college... It's very fuzzy... The first word is "Calculus"... Wait!
There's more... It's... It's... The letter "D"! I wonder what it could
mean...
(Oh, yeah-- Paul gets to do any/all derivations and integrations. :-)
-Clay
(I was out sick yesterday, so I'm catching up on all my "important" e-mail
now. ;-)
Clayton N. Cowgill Engineering Manager
_______________________________________________________________________
/\ Diamond Multimedia Systems, Inc.
\/ Communications Division http://www.supra.com/
